posted by cahaz on Feb 7, 2005:
oh well, this shouldn't be too difficult. with only 1 minute(aprox.) i noticed that each leters have 8 characters, each characters can be 0 or 1... well, not every. i also noticed that each letters' characters beging with 0, followed by 1. then the next number can be 0 or 1. if the next number is 0, then the letter is capital. if it's 1, then it's a ''normal'' letter. Then i saw that the last number concorded with the each letter number (A being the First letter of the Alphabet, B the second,.... And Z the 26th) If the number is par, the last number of the binary sequence will be 0. If not, it will be one.
so, to recapitulate,
-every Letters begin like this : 01XXXXXX
-Then, If the Letter Is Capital : 010XXXXX
-If it's a ''normal'' letter :011XXXXX
-If the Letter's Number (A is the first letter, Z is the 26th) is par (or can be divided by two without a point) , then the last number of the binary sequence will be 0. if not, it will be 1.
so: 01(x)XXXX0 or 01(x)XXXX1
if you whant you can follow with the website legit linked, because it doesn't ends here!
------------------------------------------
there's only 4 numbers to ''decode'':
--The Binary Number before the last one is a bit more complex (well, to explain anyway). See, The ''2nd'' last number of A( or a) is 0, The ''2nd'' last of B (or b) is 1 and the one of C (or c) is 1 too. Now you'll see the link, D's ''2nd last'' is 1 just like E (or e) and F and G is 0, and it continue like that. so,
Code:
abcdefghijklmnopqrstuvwxyz
0110011001100110011001
Just notice how it begins (by 0, and then 1) and how it finishes (by 1)
--the 3rd number from the right (wich i'll call ''3rd last'') (the 3rd number from the right is the 6th from the left btw) is the same thing as the ''2nd last'', but the ''1''s and ''0''s are in pack of 4 now. and it begin like if A haves the second ''0'' of is pack.
so:
Code:
A------------------------------------------Z
00011110000111100001111000
- The ''4th last'' (damn, i hat those names!), or simply 5th one also use the same ''package'' style, but now it's not in package of 2 or 4, but 8 (if you didn't notice,
you multiply the number by two to know how to do the 4th number... did i already spoiled the end?) and again, A begin as the 2nd 0 of the package (wich is a package of 8 same number now) and this can be aplied for every ''package'' style of numbers in the binary code, so the 4th number don't do exception. the 4th number of the binary code is in package of 16 (everyone understand when i say ''package?'')
Everyone understood? so to recapitulate a last time:
-the first two numbers of a letter in binary are: 0 followed by 1 (01)
-then, for the third, 0 for a capital letter and 1 for a ''normal'' one
-the fourth is in package of 16, Letter A's fourth binary number is the second 0 of
is ''package''. so there's 15 ''0'' left before the first ''1'' and there will be 15 ''1''s left
after this one to finnally see a ''0'' again
-the fifth is in package of 8, Letter A's 5th binary number is the second 0 of is ''package''. so there's 7 ''0'' left before the first ''1'' and there will be 7 ''1''s left after this one to finnally see a ''0'' again
-the sixth is in package of 4, Letter A's 6th binary number is the second 0 of is ''package''. so there's 3 ''0'' left before the first ''1'' and there will be 3 ''1''s left after this one to finnally see a ''0'' again (for those who would ask: yeah, i just copy\stick here and replace the numbers :smt043 )
-the seventh is in package of 2, Letter A's 7th binnary number is the second 0 of is ''package. so there's 1 ''0'' left before the first ''1'' and there will be 1 ''1''s left after this one to finnally see a ''0'' again''
-the last number alternate from 0 to 1 and from 1 to 0. it begins with 1(A) and finishes by 0 (Z)
Voila! now you just have to remember those and you'll be good! I never actually saw a letter in binary before this and really did find this in aprox. 1 min. hope it will help and that i didn't wrote this for nothing. :smt043 ias anyone read everything 'till the end anyway? :smt043
so, like i said earlier, this isn't that though.
Edit: Phew! i think it's the longest reply i posted! :smt042 but like someone already said: ''sorry if i write this letter this long, i didn't have the time to do it shorter.'' :smt043 if i made any mistakes (other than english and grammar mistakes, i know
) please let me know.
someone who had alot of free time to wrote this,
cahaz.